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50x^2-49x-108=0
a = 50; b = -49; c = -108;
Δ = b2-4ac
Δ = -492-4·50·(-108)
Δ = 24001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{24001}}{2*50}=\frac{49-\sqrt{24001}}{100} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{24001}}{2*50}=\frac{49+\sqrt{24001}}{100} $
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